Archive > Frakass > The Frakass' Multiverse > Everywhere Else In The Multiverse... > A Year Of The Twos > [BE] A Year Of The Twos 34
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[BE] A Year Of The Twos 34 By Frakass -- Report

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And the numbers of the week are (for each breast):

(Day / Date / Diameter / Volume / Mass)
226 / Aug14 / 4.129 Quadrillion km / 36.86 Quattuordecillion km3 / 35.02 Septendecillion T
227 / Aug15 / 5.202 Quadrillion km / 73.71 Quattuordecillion km3 / 70.02 Septendecillion T
228 / Aug16 / 6.554 Quadrillion km / 147.4 Quattuordecillion km3 / 140 Septendecillion T
229 / Aug17 / 8.257 Quadrillion km / 294.8 Quattuordecillion km3 / 280.1 Septendecillion T
230 / Aug18 / 10.4 Quadrillion km / 589.7 Quattuordecillion km3 / 560.2 Septendecillion T
231 / Aug19 / 13.11 Quadrillion km / 1.179 Quindecillion km3 / 1.12 Octodecillion T
232 / Aug20 / 16.5 Quadrillion km (1738 Light Years) / 2.359 Quindecillion km3 / 2.241 Octodecillion T

...And there are still 133 days to go!

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Comments
Resileaf

Posted by Resileaf 2 years ago Report

Looking forward to seeing the Milky Way being obscured entirely next week~

NotBatman

Posted by NotBatman 2 years ago Report

technically speaking, its gonna be a NEW milky way, just not one named due to Hera's lactations this time around :P

Firebird22

Posted by Firebird22 2 years ago Report

well she won't feel small for a long time again

Wheatmemes1717

Posted by Wheatmemes1717 2 years ago Report

The new Stellaris update looks great

carlj

Posted by carlj 2 years ago Report

If this was happening in Warhammer 40K, Slaneesh would be getting their head out of the Eye of Terror with a pair of binoculars XD

hcallahan197

Posted by hcallahan197 2 years ago Report

This would cause them to collapse and become a star, heh

Indighost

Posted by Indighost 2 years ago Report

How many stars is she encompassing at this time?

stratokummulus

Posted by stratokummulus 2 years ago Report

"The true stellar density near the Sun is estimated as 0.004 stars per cubic light year, or 0.14 stars pc^−3. When combined with estimates of the stellar masses, this yields a mass density estimate of 4×10−24 g/cm³ or 0.059 solar masses per cubic parsec."
( https://en.wikipedia.org/wiki/Stellar_density )

Since most of Chen is still within the thickness of milky way's thin disk (718–1,470 ly), we can still estimate the number of stars with this number. As her volume is 5.5e+9 ly³ or 160 million cubic parsecs (2 volumes of spheres with 1738 ly in diameter (533 parsec)), that means she is displacing about 22 million stars, most of them red dwarfs with relatively low mass. With 0,059 sun masses per cubic parsec, their cumulative mass is 9.4 million times that of our sun, or 1.9e+37 kg, 2.3 times the mass of the supermassive black hole in the center of our galaxy, or about the mass of Chen 11 weeks ago ( https://aryion.com/g4/view/790971 ).

It is difficult to estimate how many of these stars did not shatter on her skin but instead found their way into her milk ducts. From other images, I estimate the nipple opening's diameter about 5 % of her breast diameter, that means there's only about a 1 in 1600 chance of not hitting her skin (1:1111 for a 6%, 1:2500 for a 4% opening diameter/bust diameter ratio), so about 14 thousand stars could have been lucky enough to enter, but this number has a high degree of uncertainty.

Indighost

Posted by Indighost 2 years ago Report

Interesting, thank you

stratokummulus

Posted by stratokummulus 2 years ago Report

Another thing that might be interesting is: what will happen to the stars which are not entering her nipples. They and the nebula that hit her skin will most likely dissipate along her surface, so she will slowly build an atmosphere mainly consistent of hydrogen and helium. But this atmosphere is very thin:

1.9e+37 kg /
1.7e+39 m² (surface of 2 spheres with d = 1,65e+19 m: 8.5e+38 m² each)
-----------
0.011 kg/m², that is 11 g/m² or 0.036 oz/ft²

Earth's atmosphere is about 10 t/m², 900 thousand times as thick, at sea level that would mean a 9 mm thick layer of air (about the diameter of a pea, half dried, or exactly that of the eponymous 9 mm bullet). Or, since gasses are compressible, let's use water depths: about 10 m of water depth equal Earth's atmosphere, but for Chen's you would only need 11 µm, which is only a seventh of the thickness of a piece of typewriter paper, or the diameter of a red blood cell, wet. And it will not become much thicker, because she will hit intergalactic space soon which is virtually empty, and the universe has a very low density overall. If each of her breasts reach the size of the visible universe, 46.5 billion light years (yes, you can look into the universe further than it is old, because it expands, and the oldest stars you see are already much further away), it will only have sixfold, and thus still not reach typewriter paper level:

1.5e53 kg /
2.3e54 m² (surface of 1 sphere with d = 9,3e+10 ly or 8.5e+26 m)
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0.065 kg/m², or 0.21 oz/ft²